Section: Circle One:
Section A1:Lindsay Bates.Classroom:Skiles 202
Section A2:Eric Forgoston.Classroom:Skiles 246
Section A3:Mohammed Sinnokrot.Classroom:Skilkes 256
Section A4:Kasso Okoudjou.Classroom:Skiles
Section A5:Marcus Sammer. Skiles 140
Section: Circle One:
Section A1:Lindsay Bates.Classroom:Skiles 202
Section A2:Eric Forgoston.Classroom:Skiles 246
Section A3:Mohammed Sinnokrot.Classroom:Skilkes 256
Section A4:Kasso Okoudjou.Classroom:Skiles
Section A5:Marcus Sammer. Skiles 140
Jenny Thompson want you to find some series"
There are several ways to get the answer to b). One: Start with the series for
(ln(1-x)):
And now substitute x^3 wherever you see an t:
Alternatively: Note that the integral of -3x^2/(1-x^3) is ln(1-x^3)
Section: Circle One:
Section A1:Lindsay Bates.Classroom:Skiles 202
Section A2:Eric Forgoston.Classroom:Skiles 246
Section A3:Mohammed Sinnokrot.Classroom:Skilkes 256
Section A4:Kasso Okoudjou.Classroom:Skiles
Section A5:Marcus Sammer. Skiles 140
1 | 0.027777777777777776` |
2 | 0.0030864197530864196` |
3 | 0.000257201646090535` |
4 | 0.000017146776406035666` |
5 | 9.525986892242036`*^-7 |
6 | 4.5361842344009695`*^-8 |
7 | 1.890076764333737`*^-9 |
8 | 7.000284312347175`*^-11 |
9 | 2.333428104115725`*^-12 |
10 | 7.070994254896137`*^-14 |
We see that n = 4 works.